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How rigid the finite ultrametric spaces can be?
- Publication Year :
- 2015
-
Abstract
- A metric space $X$ is rigid if the isometry group of $X$ is trivial. The finite ultrametric spaces $X$ with $|X| \geq 2$ are not rigid since for every such $X$ there is a self-isometry having exactly $|X|-2$ fixed points. Using the representing trees we characterize the finite ultrametric spaces $X$ for which every self-isometry has at least $|X|-2$ fixed points. Some other extremal properties of such spaces and related graph theoretical characterizations are also obtained.<br />Comment: 19 pages, 4 figures
- Subjects :
- Mathematics - Metric Geometry
54E35
Subjects
Details
- Database :
- arXiv
- Publication Type :
- Report
- Accession number :
- edsarx.1511.08133
- Document Type :
- Working Paper