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There is no triangulation of the torus with vertex degrees 5, 6, ..., 6, 7 and related results: Geometric proofs for combinatorial theorems
- Source :
- Geom. Dedicata 166:1 (2013), 15-29
- Publication Year :
- 2012
-
Abstract
- There is no 5,7-triangulation of the torus, that is, no triangulation with exactly two exceptional vertices, of degree 5 and 7. Similarly, there is no 3,5-quadrangulation. The vertices of a 2,4-hexangulation of the torus cannot be bicolored. Similar statements hold for 4,8-triangulations and 2,6-quadrangulations. We prove these results, of which the first two are known and the others seem to be new, as corollaries of a theorem on the holonomy group of a euclidean cone metric on the torus with just two cone points. We provide two proofs of this theorem: One argument is metric in nature, the other relies on the induced conformal structure and proceeds by invoking the residue theorem. Similar methods can be used to prove a theorem of Dress on infinite triangulations of the plane with exactly two irregular vertices. The non-existence results for torus decompositions provide infinite families of graphs which cannot be embedded in the torus.<br />Comment: 14 pages, 11 figures, only minor changes from first version, to appear in Geometriae Dedicata
- Subjects :
- Mathematics - Combinatorics
Mathematics - Geometric Topology
05C10, 30F10, 57M50
Subjects
Details
- Database :
- arXiv
- Journal :
- Geom. Dedicata 166:1 (2013), 15-29
- Publication Type :
- Report
- Accession number :
- edsarx.1207.3605
- Document Type :
- Working Paper
- Full Text :
- https://doi.org/10.1007/s10711-012-9782-5