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Calculation of nonleptonic kaon decay amplitudes fromK→πmatrix elements in quenched domain-wall QCD

Authors :
Junichi Noaki
T. Yoshié
R. Burkhalter
Kazuyuki Kanaya
Yoshinobu Kuramashi
K. Nagai
Akira Ukawa
M. Okawa
N. Ishizuka
Shinji Ejiri
Yasumichi Aoki
Y. Iwasaki
T. Izubuchi
Y. Taniguchi
Shoji Hashimoto
Masataka Fukugita
S. Aoki
T. Kaneko
V. Lesk
Source :
Physical Review D. 68
Publication Year :
2003
Publisher :
American Physical Society (APS), 2003.

Abstract

We explore application of the domain wall fermion formalism of lattice QCD to calculate the $K\to\pi\pi$ decay amplitudes in terms of the $K\to\pi$ and $K\to 0$ hadronic matrix elements through relations derived in chiral perturbation theory. Numerical simulations are carried out in quenched QCD using domain-wall fermion action for quarks and an RG-improved gauge action for gluons on a $16^3\times 32\times 16$ and $24^3\times 32\times 16$ lattice at $\beta=2.6$ corresponding to the lattice spacing $1/a\approx 2$GeV. Quark loop contractions which appear in Penguin diagrams are calculated by the random noise method, and the $\Delta I=1/2$ matrix elements which require subtractions with the quark loop contractions are obtained with a statistical accuracy of about 10%. We confirm the chiral properties required of the $K\to\pi$ matrix elements. Matching the lattice matrix elements to those in the continuum at $\mu=1/a$ using the perturbative renormalization factor to one loop order, and running to the scale $\mu=m_c=1.3$ GeV with the renormalization group for $N_f=3$ flavors, we calculate all the matrix elements needed for the decay amplitudes. With these matrix elements, the $\Delta I=3/2$ decay amplitude shows a good agreement with experiment in the chiral limit. The $\Delta I=1/2$ amplitude, on the other hand, is about 50--60% of the experimental one even after chiral extrapolation. In view ofthe insufficient enhancement of the $\Delta I=1/2$ contribution, we employ the experimental values for the real parts of the decay amplitudes in our calculation of $\epsilon'/\epsilon$. We find that the $\Delta I=3/2$ contribution is larger than the $\Delta I=1/2$ contribution so that $\epsilon'/\epsilon$ is negative and has a magnitude of order $10^{-4}$. Possible reasons for these unsatisfactory results are discussed.

Details

ISSN :
10894918 and 05562821
Volume :
68
Database :
OpenAIRE
Journal :
Physical Review D
Accession number :
edsair.doi...........ca02f5adb18c46bb4d9d3657c7b18166