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A remark on Neuwirth and Newman’s paper: 'Positive 𝐻^{1/2} functions are constants'
- Source :
- Proceedings of the American Mathematical Society. 23:147
- Publication Year :
- 1969
- Publisher :
- American Mathematical Society (AMS), 1969.
-
Abstract
- PROOF. By a theorem of Rudin a function gEH' in U whose boundary values are real a.e. on I can be analytically continued to D [3, p. 59]. The lemma follows on applying Rudin's result to gi= (1/2) (fl+f2) and g2=(i/2) (fi-f2). PROOF OF THEOREM 1. By a well-known decomposition theorem [2, p. 87], f(z)=B(z)F2(Z), where B(z) is a Blaschke product and F(z) EH1. Since the boundary values of B (z) have absolute value one a.e. on K, we have a.e. on I, f(ei0)= |f(eio)I, or B(ei0)F2(ei0) = F2(ei0) |, and hence
Details
- ISSN :
- 10886826 and 00029939
- Volume :
- 23
- Database :
- OpenAIRE
- Journal :
- Proceedings of the American Mathematical Society
- Accession number :
- edsair.doi...........61d4c00cb833b66207b155f6edb828fc