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Gauss Sum of Index 4: (2) Non-cyclic Case.
- Source :
- Acta Mathematica Sinica; May2006, Vol. 22 Issue 3, p833-844, 12p, 2 Charts
- Publication Year :
- 2006
-
Abstract
- Assume that m ⩾ 2, p is a prime number, (m,p(p - 1)) = 1, -1 ∉ (p) ⊂ (∤/m∤)* and [(∤/m∤)* : (p)] = 4. In this paper, we calculate the value of Gauss sum G(X) = Σ<subscript>x∈F*<subscript>q</subscript></subscript>X(x)ζ<superscript>T(x)</superscript><subscript>P</subscript> over ...<subscript>q</subscript>, where q = p<superscript>f</superscript>, f = φ(m)/4, X is a multiplicative character of ...q and T is the trace map from ...q to ...p. Under our assumptions, G(X) belongs to the decomposition field K of p in ℚ(ζ<subscript>m</subscript>) and K is an imaginary quartic abelian number field. When the Galois group Gal(K/ℚ) is cyclic, we have studied this cyclic case in another paper: "Gauss sums of index four: (1) cyclic case" (accepted by Acta Mathematica Sinica, 2003). In this paper we deal with the non-cyclic case. [ABSTRACT FROM AUTHOR]
Details
- Language :
- English
- ISSN :
- 14398516
- Volume :
- 22
- Issue :
- 3
- Database :
- Complementary Index
- Journal :
- Acta Mathematica Sinica
- Publication Type :
- Academic Journal
- Accession number :
- 21080929
- Full Text :
- https://doi.org/10.1007/s10114-005-0645-y