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Totally ordered sets and the prime spectra of rings.
- Source :
- Communications in Algebra; 2017, Vol. 45 Issue 1, p411-419, 9p
- Publication Year :
- 2017
-
Abstract
- LetTbe a totally ordered set and letD(T) denotes the set of all cuts ofT. We prove the existence of a discrete valuation domainOvsuch thatTis order isomorphic to two special subsets of Spec(Ov). We prove that ifAis a ring (not necessarily commutative), whose prime spectrum is totally ordered and satisfies (K2), then there exists a totally ordered setU⊆Spec(A) such that the prime spectrum ofAis order isomorphic toD(U). We also present equivalent conditions for a totally ordered set to be a Dedekind totally ordered set. At the end, we present an algebraic geometry point of view. [ABSTRACT FROM AUTHOR]
- Subjects :
- SET theory
RING theory
EXISTENCE theorems
MATHEMATICAL domains
ALGEBRAIC geometry
Subjects
Details
- Language :
- English
- ISSN :
- 00927872
- Volume :
- 45
- Issue :
- 1
- Database :
- Complementary Index
- Journal :
- Communications in Algebra
- Publication Type :
- Academic Journal
- Accession number :
- 118710284
- Full Text :
- https://doi.org/10.1080/00927872.2016.1175583