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1.In the complexes B10H12L2 the B10H12 fragment behaves as a delocalized electron-deficient acceptor.2.The movement of the valence MO's of the boron atoms in the B10H12 fragment to deeper positions in the case of an NH3 ligand may be caused by an interaction involving the d orbitals of the nitrogen atom. Another explanation for the difference in the ligand-skeleton chemical bonding may be the steric effects associated with the geometry of N(Et)3.

1.From a comparison of the $$CuL_{\alpha _{1, 2} } $$ and BKa, spectra of Cu2B10H10 it follows that the upper valence MO in this salt are build mainly from Cu+ 3d orbitals (G and H maxima). The deeper MO are represented mainly by the 2p orbitals of the B atoms. The BKa and CuL $$CuL_{\alpha _{1, 2} } $$ , overlap of the spectra indicates that MO of the mixed p-d type are present, which can be explained by the participation of the Cu+ 3p orbitals in forming the chemical bond.2.A charge transfer of ~0.5 e from the B10H102- ion to the Cu+ ions occurs in the salt Cu2B10H10 when compared with Cs2B10H10.3.Two vertex and four equatorial B atoms of the anion participate in forming the bond in Cu2B10H10. The equatorial atoms undergo the greatest change in the bond energy, which can be explained by assuming their participation in the simultaneous formation of both the three-center B-Cu-B bond and the B-H-Cu bridge bond.4.From an estimate of the charge value of the Cu+ ion and the x-ray spectral data it can be postulated that the bond with Cu2B10H10 bears a partially covalent character, which is caused by the donor-acceptor mechanism for the interaction of the Cu ion with the B10H102- ion.