In this paper we prove the following theorem for simultaneous approximation in L spaces for p r,there exists a polynomial p of degree n, such that for all j = 0, . . . , mwe have|f z p z | c ωA∗ .f ; 0 , ∀z ∈ ∂ ,and p zC # f zC , l # 1,... , q,Where C is independent of n and z.HereωA∗ g; δ : # supG∈ : HEA -Ig; : ∩ B z; δ LM,B(N;δ # %ξ ∈ "; |ξ N| δ;, E g;M :# inf %‖g p‖Q; P complex polynomial of degree m;.Theorem 1.1was proved by (N.N.Vorob’ev) in [6] for the so-called domains of type1.1in the complex plane (including the unit disk) and Theorem1.2 was proved by (V.V. Andrievskii, I. Pritsker and R. Varga)in [1] for general continuain the complex plane (including the unit disk).In our paper , we will re-state them here for the particular case of unit disk only. Unfortunately, the constants appearing in these estimates, are claimed in the corresponding papers, as independent of n and zonly, without to be mentioned the independence of ftoo. Because of complicated technical details, it seems to be very difficult to deduce from the proofs of Theorems 1.1and 1.2that possibly these constants are independent of f too. For this reason, in the case of unit disk, by our main result Theorem 3.1, in the following section we improve these theorems to the spaces L ,for p R 1 with new simple proof which clearly shows that the constant is independent of n, z and f too. 2. The Auxiliary results To prove our theorem we need the following definitions and results for f ∈ A , σ ,T f z # TU-∑ TX XY T f z ,where TX f z # ∑ Z [ \ ! X Y\ z Lemma 2.1: T^X f z # TX f ^ z . Proof: TX f z # ∑ Z [ \ ! X Y\ z ,k# 0,... ,mTX f z # ∑ j Z [ \ ! X Y\ z # ∑ j Z [`a \ b ! X Y\ z # ∑ IZ [ Lb \ ! X Y\ z # TX f ^)(z)∎ Lemma 2.2: σd , X f z # σd X, If X L z Simultaneous approximation by complex polynomials 1805 Proof: σ ,T f z # TU-∑ TX XY T f z wheren # 2n, h # n m ,k=0,...,m,σd , f z # U-∑ TX d XYd U f z bylemma2.1weget σd , ^ f z # 1 n m> 1 f TX d XYd U f ^ z # σd -, f ^ z σ^^d , f z # 1 n m> 1 f TX d d XYd U f ^^ z # σd d, f ^^ z σ^^^d , f z # 1 n m> 1 f TX g d XYd U f ^^^ z # σd g, f ^^^ z ⋮ σd , X f z # 1 n m> 1 f TX X d XYd U fX z # σd X, fX z ∎ Lemma 2.3 [5]:‖f σ , f ‖i A∑ jk`lm[ Z n U UY\ where: E f i # inf %‖f p‖i, p is polynomail of degree } ,A is an absolute constant independent of f, n and m. Lemma 2.4[3]: supp∈qr,st|p x | vw s r‖p ‖x qr,st ,0 R y R ∞ Proposition 2.5: ∥ f σ ,T f ∥ c p ∑ jk`lm[ Z w U UY\ where c p is an absolute constant independent of f, n and m. Proof: It is sufficient to show E U f i c p E U f Assume E f #∥ f Q ∥~ , 0 R R ∞ ,
∈ 2C # n AndPd be apolynomial of best approximation of f.Then we may writef p # ∑ pdk[ i Ypdk[`a .Thus S.N.Bernstein inequality [2] yieldsE f i #∥ ∑ pd Y\ pd ∥iThen by lemma 2.4we obtain E f i c p ∥ fpd pd Y\ ∥ c p ∥ f Q ∥~ ......... 1 1806 Eman Samir Bhaya and Asmaa Raheem Hadi # c p E f Hence∥ f σ , f ∥ ∥ f σ , f ∥i A∑ jk`lm[ Z n U UY\ Then from(1)we get ∥ f σ , f ∥ c p ∑ jk`lm[ Z w U UY\ ∎ Lemma 2.6: Ifn R > 1,then E Uf E f Proof: E Uf # inf kma∈∏kma ∥ f p U∥ , where ∏ ∏ Uinf k∈∏k ∥ f p ∥ # E f ∎ Lemma 2.7:∥ f σd X, f ∥ c p E U X f where c p is an absolute constant independent of f, n and m. Proof: UsingProposition 2.5 to obtain ∥ f σd X, f ∥ c p f E U XU f n m > j > 1 d X Y\ c p E U X f f 1 n m> j > 1 d X Y\ c p E U X f 2n k > 1 n m> 1 byn msothat∥ f σd X, f ∥ c p E U X f d UUc p 2m > 1 E U X f ∎ Lemma 2.8[4]: E f i c p n E f i where c p is a constant depending only on p. Proposition 2.9: E f c p n E f where c p is a constant depending only on p. Proof: Using lemma2.8 we have f c p E f i c p n E f i Using the same lines used for the proof of proposition 2.5we can get E f c p E f i c p n E f i c p n E f ∎ 3. The main result Theorem 3.1:∥ f X P X ∥ c p n UXE f Simultaneous approximation by complex polynomials 1807 where c p is a constant depending only on p. Proof: ∥ f X P X ∥ ∥ f X σd , X f ∥ >∥ σd , X f p X ∥ Usinglemma2.2weget∥ f X P X ∥ #∥ f X σd X, f X ∥ >∥ σd , X f p X ∥ Usinglemma2.7weobtain ∥ f X P X ∥ c p E U X f X >∥ σd , f p X ∥ by Bernstein’s inequality we have∥ f X P X ∥ c p E U X f X > 2n X ∥ σd , f p ∥ c p E U X f X > C p nXq∥ σd , f f ∥ >∥ f P ∥ c p E U X f X > C p nXqE U f > E f t c p E U X f X > C p nXE f byProposition2.9weget∥ f X P X ∥ C p E U X f X > C p nXn E f by Proposition 2. 9we obtain ,for n > m k ∥ f X P X ∥ C p n > m k UXE f > C p n UXE f C p n UXE f ∎